Here’s how to use contain() function.
Description:
Check whether a given data object is a member of a certain sequence.
Syntax:
A.contain(xi,…)
Note:
The function checks whether parameter xi,… are members of sequence A or not; the number of parameters x is i. Return true if all parameters are members of sequence A, and false if not.
Parameter:
|
A |
A sequence object or an expression that returns one |
|
xi |
Data object, which can be a number, a string or a sequence |
Option:
|
@b |
The option means that sequence A is ordered, based on which a binary search is performed in an ascending or descending order |
|
@h |
Use HASH method to increase computing efficiency; for scenarios where the sequence has a large amount of data |
Return value:
Boolean value
Example:
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A |
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1 |
=[1,2,8,4,5,6,7,8] |
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2 |
=A1.contain(8) |
true. |
|
3 |
=A1.contain(9) |
false. |
|
4 |
=[1,2,3,4,5,6,7,8,9].contain@b(8) |
Use binary search when the sequence is ordered; the result is true. |
|
5 |
=[[1,2,3,4,5,6,7,8],[3]].contain ([3]) |
true. |
|
6 |
[1,3,6,aaa] |
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|
7 |
=A6.contain("aaa") |
true. |
|
8 |
=A1.contain(8,1) |
true. |
|
9 |
=A1.contain(8,9) |
false. |
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|
A |
B |
C |
|
|
1 |
10000 |
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|
2 |
=to(A1) |
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3 |
>A2(1)=0 |
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4 |
for A2 |
if A4>0 |
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5 |
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=A1.step(A4,A4).to(2,) |
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6 |
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>A2(C5)=0 |
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7 |
=A2.select(~>0) |
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|
A7’s result is a sequence consisting of prime numbers within 10,000. |
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8 |
=A7.contain@h(4447) |
|
|
true; judge whether 4447 is a prime number, during which @h option is used to increase computing efficiency. |
Related functions: