median()
Here’s how to use median() function.
A.median( k:n )
Description:
Divide a sequence into multiple segments and return the specified bordering member(s).
Syntax:
|
A.median(k:n) |
Divide sequence A into n segments evenly according to its length and return the bordering member between the kth segment and the (k+1)th segment |
|
A.median(k:n,x) |
Calculate expression x over each member of sequence A to generate a new sequence that will be ordered automatically, then divide the new sequence into n segments evenly according to its length and return the bordering member between the kth segment and the (k+1)th segment |
Note:
The function returns a sequence of the bordering members between every two segments when parmeter k is absent but parameter n is present.
When parameter x is present, prameters k,n should be always in place. When prameters k,n are absent, if the length of the sequence is an odd, return the median member value; if it is an even, return the average value of the two members in the middle. Perform a logical division if the length of the sequence is indivisible.
Parameter:
|
A |
A sequence |
|
k |
The kth segment (1=<k<=n); return the bordering members of between every two segments as sequence when k is absent |
|
n |
The number of to-be-divided segments, which is greater than 1 and whose default is 2; can be omitted when parmeter k is absent |
|
x |
An expression |
Return value:
A number or a sequence
Example:
|
|
A |
|
|
1 |
=[1,2,3,4,5,6,7,8] |
|
|
2 |
=A1.median() |
As all parameters are absent and the length of the sequence is an even number, the function returns the average of the two members in the middle, that is (4+5)/2=4.5 |
|
3 |
=A1.median(2:3) |
The sequence is divided as follows:
Divide the sequence into 3 segments and return the bordering member between the second segment and the third on, which is 6 |
|
4 |
=A1.median(:3) |
As no segment is specified, return the bordering members between every two segments as a sequence, which is [3,6] |
|
5 |
=A1.median(:10) |
The sequence is divided as follows: Result: [1,2,3,4,4.5,5,6,7,8] |
|
6 |
=A1.median(:,~%2) |
Divide each member of sequence A1 by 2 and get the remaider to generate a new sequence in ascending order: [0,0,0,0,1,1,1,1]; As prameters k,n are absent and the the length of the sequence is an even, the function returns the average value of the two members in the middle: (0+1)/2=0.5 |
|
7 |
A1.median(2:3,~%2) |
Divide the new sequence evenly into 3 segments and return the bordering member between the 2nd and the 3rd : 1 |
