# median()

Here’s how to use median() function.

## A.median( k:n )

Description:

Divide a sequence into multiple segments and return the specified bordering member(s).

Syntax:

 A.median(k:n) Divide sequence A into n segments evenly according to its length and return the bordering member between the kth segment and the (k+1)th segment A.median(k:n,x) Calculate expression x over each member of sequence A to generate a new sequence that will be ordered automatically, then divide the new sequence into n segments evenly according to its length and return the bordering member between the kth segment and the (k+1)th segment

Note:

The function returns a sequence of the bordering members between every two segments when parmeter k is absent but parameter n is present.

When parameter x is present, prameters k,n should be always in place. When prameters k,n are absent, if the length of the sequence is an odd, return the median member value; if it is an even, return the average value of the two members in the middle. Perform a logical division if the length of the sequence is indivisible.

Parameters:

 A A sequence k The kth segment (1=

Return value:

A number or a sequence

Example:

 A 1 =[1,2,3,4,5,6,7,8] 2 =A1.median() As all parameters are absent and the length of the sequence is an even number, the function returns the average of the two members in the middle, that is (4+5)/2=4.5 3 =A1.median(2:3) The sequence is divided as follows: Divide the sequence into 3 segments and return the bordering member between the second segment and the third on, which is 6 4 =A1.median(:3) As no segment is specified, return the bordering members between every two segments as a sequence, which is [3,6] 5 =A1.median(:10) The sequence is divided as follows: Result: [1,2,3,4,4.5,5,6,7,8] 6 =A1.median(:,~%2) Divide each member of sequence A1 by 2 and get the remaider to generate a new sequence in ascending order: [0,0,0,0,1,1,1,1]; As prameters k,n are absent and the the length of the sequence is an even, the function returns the average value of the two members in the middle: (0+1)/2=0.5 7 A1.median(2:3,~%2) Divide the new sequence evenly into 3 segments and return the bordering member between the 2nd and the 3rd : 1